5[x+1]+7[x+3]=146

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Solution for 5[x+1]+7[x+3]=146 equation:


Simplifying
5[x + 1] + 7[x + 3] = 146

Reorder the terms:
5[1 + x] + 7[x + 3] = 146
[1 * 5 + x * 5] + 7[x + 3] = 146
[5 + 5x] + 7[x + 3] = 146

Reorder the terms:
5 + 5x + 7[3 + x] = 146
5 + 5x + [3 * 7 + x * 7] = 146
5 + 5x + [21 + 7x] = 146

Reorder the terms:
5 + 21 + 5x + 7x = 146

Combine like terms: 5 + 21 = 26
26 + 5x + 7x = 146

Combine like terms: 5x + 7x = 12x
26 + 12x = 146

Solving
26 + 12x = 146

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-26' to each side of the equation.
26 + -26 + 12x = 146 + -26

Combine like terms: 26 + -26 = 0
0 + 12x = 146 + -26
12x = 146 + -26

Combine like terms: 146 + -26 = 120
12x = 120

Divide each side by '12'.
x = 10

Simplifying
x = 10

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